At an amusement park, the probability that a child eats popcorn and cotton candy is 0.58. the probability that a child eats popcorn is 0.69 and the probability that a child eats cotton candy is 0.87. what is the probability (rounded to the nearest hundredth) that a child eats popcorn given that the child has already eaten cotton candy?

hint:
p(a|b)=p(a∩b) / p(b)

0.84

0.67

0.79

0.40

The correct answer option is 0.67.

Step-by-step explanation:

We are given that the probability that a child eats popcorn and cotton candy is 0.58, probability that a child eats popcorn is 0.69 and the probability that a child eats cotton candy is 0.87.

We are to find the probability that a child eats popcorn given that the child has already eaten cotton candy.

P (eats popcorn and has already eaten cotton candy) = = 0.67

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3