If 5 times a number is increased by 4, the result is at least 19. find the least possible number that satisfies these conditions.

3

Step-by-step explanation:

5 times a number would be 5x, then increase that by 4 is 5x+4.  The problem then says 5x + 4 ≥ 19.  If we solve for x then we get x ≥ 3 so x has to be greater than or equal to 3, so the smallest number it could be is 3.  You can even try any number smaller than 3 and see it doesn't work.  even something like 2.9

x ≥ 3  

Step-by-step explanation:

Let the number = x

5 × the number = 5x

Increased by 4 means 5x +4

   Is at least 19 means ≥ 19

5x + 4 ≥ 19

5x       ≥ 15      Subtracted 4 from each side

 x       ≥    3      Divided each side by 5

The smallest possible number that satisfies the conditions is x = 3.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

step-by-step explanation: 4 cause 2+2=4