Abag contains 10 counters. 6 of them are white. a counter is taken at random and not replaced. a second counter is taken out of the bag at random. calculate the probability that only one of the two counters are white.

Step-by-step explanation:

Given:

There are 10 counters.

6 of the counters are white.

Two counters are drawn one after another without replacement.

To Find:

The probability that only one of the two counters is white

Explanation:

P(Only one of the two counters is white)

= P(white) x P( not white) + P(not white) x p(white)

Solution:

P(Only one of the two counters is white) = 6/10 x 4/9 + 4/10 x 6/9

P(Only one of the two counters is white) = 4/15 + 4/15

P(Only one of the two counters is white) = 8/15

The probability is 8/15

incomplete question. how do you expect anyone to you when you do not post the question in its entirety?

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.