Arobot moves at a constant speed. the distance it moves and the time it spends moving are shown in this table:

d = 0.7*t

Step-by-step explanation:

Given data,

  Time          Distance

   10                 7

   15                10.5

   20                 14

From analysis,

1) d1/t1 = 7/10 = 0.7

2) d2/t2 = 15/20 = 0.7

3) d3/t3 = 14/20 = 0.7

It can be analysed from the figure that, at every point d/t = 0.7

Therefore, the relationship between t and d is

d = 0.7*t

or

t = d/0.7  

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

360/29

step-by-step explanation: