Solve y^2+7y+12=0 by completing the square.

y = -3, -4

Step-by-step explanation:

Formula is (b/2)^2

So...

(y+7/2)^2 - 1/4 = 0

Add 1/4 to each side

(y+7/2)^2 = 1/4

Square root...

y+7/2 = +-1/2

Add

y = -3, -4

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!