Amailbox is 15 inches long and 8 inches wide. the height of the mailbox before the curve is 6 inches. what is the volume of the mailbox? use 3.14 for pi.

First, we'll find the area of the base. (To find the volume of any prism, find the area of the base, then multiply by the length/height.) It consists of a rectangle and a semicircle put together. To find the area of the semicircle, we'll just use the formula for the area of a circle, then divide by two. Area of a circle = radius² × 3.14. If the diameter of this circle is 8, then halve that to find the radius, which is 4. 4² = 16. 16 × 3.14 = 50.24. Now, 50.24/2 = 25.12. 25.12 is the area of the semicircle. Then, find the area of the rectangle. Formula for that is base × height. 6 × 8 = 48. Now add the two areas. 25.12 + 48 = 73.12. 
Simply multiply that area by the length to find the volume. 73.12 × 15 = 1096.8. 
The volume of the mailbox is 1,096.8 in³. (Don't forget to label!)
Hope that helped!

We see that we can cut it up
1 rectangular prism (bottom part that is like a box0
1 half dome=1/2 cylinder

V of rectangular prism=LWH
v of cylinder=hpir^2

retangualr prism volume
L=15
W=8
H=6
V=15*6*8=720 in^2

1/2 cylinder
8=diameter
d/2=r
8/2=4=r
h=15
r=4
V=15pi4^2
v=15pi16
v=240pi
pi=3.14
v=753.6
half cylinder so multiply by 1/2
752.6 tiems 1/2=376.8 in^3

add
prism+1/2sphere=volume=720+376.8=1096.8 in^3

1096.8 in^3

Yep u would so yeah