Suppose y varies directlly with x. if y= 6 when x=2 find x when y= 12

The value of x = 4 when the value of y = 12

Step-by-step explanation:

∵ y α x ⇒ it is direct variation

- It means y increase when x increase

∴ y = kx ⇒ where k is a constant

- To find the value of k we will substitute the values of x

  and y in the equation above

- If y = 6 when x = 2

∴ 6 = k(2) ⇒ divide two sides by 2

∴ k = 3

∴ y = 3x ⇒ equation of variation

- To find the value of x when y = 12

- Substitute the value of y in the equation of variation

∴ 12 = 3x ⇒ divide both sides by 3

∴ x = 4

* The value of x = 4 when the value of y = 12

x=4

Step-by-step explanation:

By definition, the direct variation eqution has the following form:

Where k is the constant.

Therefore, if If when , you can calculate k as following:

-Substitute values.

- Solve for k.

Then:

Then, when , you can calculate the value of x as it is shown below:

-Substitute values.

- Solve for x.

Then:

only 10/60 isn't equivalent

hope this : )

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°