If g(x)=x^2-2x+1 were shifted 2 units to the left, what would be the new equation, h(x)?

h(x) = (x+2) ^2 -2x -3

Step-by-step explanation:

If we have to shift 2 units left the we have to replace x by x+2 i.e

h(x) = (x+2)^2-2(x+2)+1

      = (x+2)^2 -2x-4 +1

       = (x+2)^2 -2x -3

answer: check all that apply, where the options?

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a