Sandy mixed 9 ml of an acidic solution with 8 ml of a 42% acidic solution, to make a 45% acidic solution. find the percent acid concentration of the first solution.

47.67%

Step-by-step explanation:

Amount of 1st solution = 9 ml

Let the percentage acid concentration of 1st solution is x%

Amount of 2nd solution = 8 ml

Percentage acid concentration of 2nd solution = 42%

Percentage acid concentration of the mixture = 45%

Amount of the mixture = 8 + 9 = 17 ml

1st Solution + 2nd Solution = Mixture

x% of 9 ml + 42% of 8 ml = 45% of 17 ml

Thus, the percent acid concentration of first solution is 47.67%

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4

x-3y=4

step-by-step e