Mathematics, 18.10.2019 17:30 Garry123

Find the probabilities of the events described and arrange them in order from the event with the lowest probability of occurrence to the event with the highest probability of occurrence.

the probability of picking a red marble from a bag containing 5 green, 3 red, and 4 blue marbles

the probability of picking a peach from a basket of fruit containing 7 peaches and 3 apples

the probability of picking a green token from a box containing 10 red, 6 blue, and 4 green tokens

the probability of picking a golf ball from a box containing 2 tennis balls and 13 golf balls

Answers: 1

Show answers

Answers

1.)the probability of picking a green token from a box containing 10 red, 6 blue, and 4 green tokens
2.)the probability of picking a red marble from a bag containing 5 green, 3 red, and 4 blue marbles.
3.)the probability of picking a peach from a basket of fruit containing 7 peaches and 3 apples.
4.)the probability of picking a golf ball from a box containing 2 tennis balls and 13 golf balls
(1 being lowest)

Answer from: Kimbeeeerly70111

The probability of picking a green token from a box containing 10 red, 6 blue, and 4 green tokens < the probability of picking a red marble from a bag containing 5 green, 3 red, and 4 blue marbles < the probability of picking a peach from a basket of fruit containing 7 peaches and 3 apples < the probability of picking a golf ball from a box containing 2 tennis balls and 13 golf balls.

i.e. 0.2<0.42<0.7<0.87

Step-by-step explanation:

Since we have given that

1) the probability of picking a red marble from a bag containing 5 green, 3 red, and 4 blue marbles

Probability would be $\dfrac{\text{Red Marble}}{Total\ marble}}=\dfrac{5}{12}=0.42$

2) the probability of picking a peach from a basket of fruit containing 7 peaches and 3 apples

Probability would be $\dfrac{Peach}{Total}=\dfrac{7}{10}=0.7$

3) the probability of picking a green token from a box containing 10 red, 6 blue, and 4 green tokens

Probability would be $\dfrac{Green}{Total}=\dfrac{4}{20}=\dfrac{1}{5}=0.2$

4) the probability of picking a golf ball from a box containing 2 tennis balls and 13 golf balls

Probability would be $\dfrac{Golf\ ball}{Total}=\dfrac{13}{15}=0.87$

We need to arrange them in order from the event with the lowest probability of occurrence to the event with the highest probability occurrence:

So, 0.2<0.42<0.7<0.87

Hence, it becomes

the probability of picking a green token from a box containing 10 red, 6 blue, and 4 green tokens < the probability of picking a red marble from a bag containing 5 green, 3 red, and 4 blue marbles < the probability of picking a peach from a basket of fruit containing 7 peaches and 3 apples < the probability of picking a golf ball from a box containing 2 tennis balls and 13 golf balls.

Answer from: Quest

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like, however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

$\bf e(\stackrel{x_1}{-2}~,~\stackrel{y_1}{2})\qquad f(\stackrel{x_2}{0}~,~\stackrel{y_2}{0}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-2}{)}\implies \implies \cfrac{-2}{0+2}\implies \cfrac{-2}{2}\implies -1 \\\\[-0.35em] ~\dotfill$

$\bf d(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-1})\qquad f(\stackrel{x_2}{0}~,~\stackrel{y_2}{0}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{)}{)}\implies \cfrac{0+1}{0+2}\implies \cfrac{1}{2} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope~of~ef}{-1\implies \cfrac{-1}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{-1}}\qquad \stackrel{negative~reciprocal}{+\cfrac{1}{1}\implies 1}}$