Mathematics, 03.02.2020 15:52 ronny80

If △hli ~ △jlk by the sss similarity theorem, then is also equal to which ratio?

Answers: 3

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Answer from: aron7596

$\rm \dfrac{HL}{JL}=\dfrac{IL}{KL}=\dfrac{HI}{JK}$

Step-by-step explanation:

Given :

$\rm \bigtriangleup HLI \sim \bigtriangleup JLK$ by the SSS similarity theorem.

$\rm \dfrac {HL}{JL} = \dfrac{IL}{KL}$

Solution :

According to SSS postulate,

KL = IL ----- (1)

HL = JL ----- (2)

HI = JK ------ (3)

From equation (1), (2) and (3) we get,

$\rm \dfrac{HL}{JL}=\dfrac{IL}{KL}=\dfrac{HI}{JK}$

For more information, refer the link given below

link

Answer from: agarza0326

Triangle HLI has sides identical in measure to the three sides of triangle JLK, then the two triangles are congruent by SSS postulate. Therefore,

$\rm \dfrac{HL}{JK}=\dfrac{IL}{KL}=\dfrac{HI}{JK}$

Given :

$\rm \Delta HLI \sim \Delta JLK$ by the SSS similarity.

According to SSS (Side Side Side) postulate:

If all three sides of a triangle are congruent to corresponding three sides of other triangle then the two triangles are congruent.

If triangle HLI has sides identical in measure to the three sides of triangle JLK, then the two triangles are congruent by SSS postulate.

Therefore, from triangle HLI and triangle JLK we get,

KL = IL ----- (1)

HL = JL ----- (2)

HI = JK ------ (3)

From equation (1) , (2) and (3) we get,

$\rm \dfrac{HL}{JK}=\dfrac{IL}{KL}=\dfrac{HI}{JK}$

For more information, refer the link given below

link

Answer from: Quest

don't report but were is the digram

step-by-step explanation:

Answer from: Quest

statement #3: proof- ang is congruent to ang ecd : angles are congruent.

step-by-step explanation:

1: the missing angles in statement #3

a.) acb

reason- the reason why the answer is acb is because angle ecd and angle acb are both the same size *that's what the word congruent means this is really simple.

2: the missing word in reason #3

c.) vertical

reason- the reason why the answer is vertical is because the angles in that diagram on figure 2 is slanted, which is vertical, and the e and a both lay on vertical lines. along with the other's, but e and a are the 2 main points you want to focus on. and c is kind of like your starting point, because c is for both angles, not just one.

i hope that was and understanding.

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