Which polynomial function has a leading coefficient of 1, roots –2 and 7 with multiplicity 1, and root 5 with multiplicity 2?

f(x) = 2(x + 7)(x + 5)(x – 2)

f(x) = 2(x – 7)(x – 5)(x + 2)

f(x) = (x + 7)(x + 5)(x + 5)(x – 2)

f(x) = (x – 7)(x – 5)(x – 5)(x + 2)

ANSWER

EXPLANATION

If the polynomial has a root -2, with multiplicity 1, then (x+2) is a factor.

If the polynomial has root, 7 with multiplicity 1, then (x-7) is a factor.

If the polynomial has root 5, with multiplicity 2, then (x-5)² is a factor of the polynomial.

The fully factored form of the polynomial is

It was given that the polynomial has a leading coefficient of 1.

Hence a=1.

This implies that,

Or

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

109 trust me

step-by-step explanation: