The length of a rectangle is 8 cm more than 3 times its width. the perimeter of the rectangle is 64 cm. show the equation that would be used to find the dimensions of the rectangle.

let w = the width. then 3(w + 8) = length. so the equation is 64 = 2(3(w + 8)) + 2w.

let w = the width. then 3w = length + 8. so the equation is 64 = 2(3w – 8) + 2w.

let w = the width. then 3w + 8 = length. so the equation is 64 = 2(3w + 8) + 2w. 64 = 2(3w + 8) + 2w

let w = the width. then 3w + 8 = length. so the equation is 64 = (3w + 8) w.

Let w = the width. Then 3w + 8 = length. So the equation is 64 = 2(3w + 8) + 2w.

Step-by-step explanation:

This is the correct answer because it satisfies both parts of the statement.

Firstly, we know that the length is 3 times the width plus 8. This gives us that answer. Those with the parenthesis would need to be distributed and would actually wind up being 3w + 24. Therefore those are not correct.

Also, the equation for perimeter is 2l + 2w. If we use that formula and put in the value we have above for length, we get the correct answer.

dd

step-by-step explanation:

dd

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