Can someone tell me what the formula of problem would be? and answer/explain how you got that answer.

Area_shaded  = 2543.742 ft^2

Step-by-step explanation:

First we find the area of the external triangle

A_triangle = base*height*0.5

A_triangle = (92 ft)*(84 ft)*0.5 = 3864 ft^2

Then we find the area of the pool (circle)

A_circle = pi*radius^2

A_circle = 3.1416*(20.5 ft)^2 = 1320.257 ft^2

The area of the shaded region

Area_shaded = A_triangle - A_circle

Area_shaded  = 3864 ft^2 - 1320.257 ft^2 = 2543.742 ft^2

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

answer:   y=2x-3

step-by-step explanation: