Which ordered pair (x, y) is a solution to the following system of equations?

{5x+4y=-14
{3x+6y=6

(-6, 4)

Step-by-step explanation:

You can use the Elimination method:

- Multiply the the first equation by -3 and the second one by 5.

- Add both equations.

- Solve for y:

- Susbtittute y=4 into any of the original equations and solve for x:

Then the ordered pair is:

(-6, 4)

(-6, 4)

Step-by-step explanation:

We are given the following two equations and we are to solve them:

--- (1)

--- (2)

Using the substitution method:

From equation (2):

Substituting this value of x in equation (1) to get:

Putting this value of y in equation (2) to find the value of x:

Therefore, (-6, 4) is the solution to the given system of equations.

1. a^4+8a^3+24a^2+32a+16

2.y^8+8y^7+28y^6+56y^5+70y^4+56y^3+28y^2+8y+1

3.x^6-3x^4y^2+3x^2y^4-y^6