What is a probability that a person chosen at random who lives in the city live in the east or west region?

0.3

Explanation:

We are given that:

Probability that a randomly chosen person lives in the East is 0.12

P(East) = 0.12 > I

Probability that a randomly chosen person lives in the West is 0.18

P(West) = 0.18 > II

Now, we want to find the probability that the randomly chosen person lives in the East or West

To do this, we will use the following formula:

P(A or B) = P(A) + P(B)

Applying this rule to our givens:

P(East or West) = P(East) + P(West)

P(East or West) = 0.12 + 0.18

P(East or West) = 0.3

Hope this helps :)

0.30

Step-by-step explanation:

The probability that a person chosen at random lives in the east region is 0.12

The probability that a person chosen at random lives in the west region is 0.18

The probability that a person chosen at random lives in east or west region;

This implies that;

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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