1/8 of the boys at a high school tried out for the football team, 1/6 tried out for the baseball team, and 1 /12 tried out for the football team and baseball team. what fraction of those who tried out for football also tried out for baseball?
a)1/12
b) 1/2
c) 1/3
d) 2/3

2/3

Step-by-step explanation:

This is a overlap question.

First Step: add the fractions. 1/8 + 1/6 + 13/12 = 66/48

the answer is 2/3

D) 2/3

Step-by-step explanation:

Let x represent the number of boys at the high school.

1/8x total tried out for football.

1/6 total tried out for baseball.

If we were to draw a Venn diagram, the intersection of the two circles would be the 1/12 of the students that tried out for both, or 1/12x.

Taking this away from the total of 1/8x for football,

1/8x - 1/12x

3/24x - 2/24x

1/24x tried out for just football.

Taking the 1/12x away from the 1/6x that tried out for just baseball,

1/6x - 1/12x

4/24x - 2/24x

2/24x = 1/12x tried out for just baseball.

Looking at those that tried out for football, 2/24 tried out for both and 3/24 total tried out for football.  This means 2 out of 3, or 2/3, of the football try outs also tried out for baseball.

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c