Afamily on a vacation drives 123 miles in 2 hours then gets stuck in traffic and goes 4 miles in the next 15 minutes. the remaining 191 miles of the trip take 3 3/4 hours. what was their average rate of speed to the nearest tenth of a mile per hour

Their average rate of speed is 53 miles per hour.

Step-by-step explanation:

Given : A family on a vacation drives 123 miles in 2 hours then gets stuck in traffic and goes 4 miles in the next 15 minutes. The remaining 191 miles of the trip take hours.

To find : What was their average rate of speed to the nearest tenth of a mile per hour ?

Solution :

We know,

Total distance traveled by family on vacation is

D= 123 miles + 4 miles + 191 miles = 318 miles

Total time taken by family on vacation is

T= 2 hours + 15 minutes + hours

T= 2 hours + hours + hours

T= hours

T= hours

T= hours

T= 6 hours

Substitute the value in the formula,

miles per hour.

Therefore, Their average rate of speed is 53 miles per hour.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b