There is a part c
part c
what is the length and width of each section?

Part A:  Width is 1/4 yard

Part C:  Each section:  L = 1/9 yard, W = 1/8 yard

Step-by-step explanation:

Part A:

The area is given as 1/12 yard² and the length is given as 1/3 yard.  The area of a rectangle is A = LW, plug in the given values and solve...

1/12 = (1/3)W

    3/12 = W   (multiply both sides by 3 to get rid of the fraction on the right)

      1/4 yard = W  (reduce the fraction on the left)

Part C:  The width is 1/4, and there are 2 squares along the width, so each section is

1/4 ÷ 2 = (1/4)*(1/2) = 1/8 yards wide

The length is 1/3 and there are 3 sections along the length, so each section is

1/3 ÷ 3 = (1/3)*(1/3) = 1/9 yards long

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

answer: the two figures are congruent.

step-by-step explanation: they're congruent because figure efgh is reflected across the x and y axis but it was also rotated.

hope it !