solution:
as, mean is defined as sum of all the observations divided by total number of observations.
and , median is mid value of the data whether arranged in ascending order or descending order.
consider, roadsters:
2,3,4,5,6,7,8,9
mean = ![\frac{2+3+4+5+6+7+8+9}{8}=\frac{44}{8}=5.5](/tex.php?f=\frac{2+3+4+5+6+7+8+9}{8}=\frac{44}{8}=5.5)
also, median=
, because number of observations is even, so median is mean of two mid values.
now, coming to bandits
2,3,4,5,6
mean = ![\frac{2+3+4+5+6}{5}=\frac{20}{5}=4](/tex.php?f=\frac{2+3+4+5+6}{5}=\frac{20}{5}=4)
median = 4, as number of observations is odd.
so, roadsters has greater median as well mean than bandits.
→option a is true about the repairs performed on 2 types of cars:
bandits have lower median and mean than roadsters.