The scores on a standardized test are normally distributed with a mean of 500 and a standard deviation of 60. jake scored 520 on the test. what percent of students scored below jake? include a step by step description of the process you used to find that percentage.

Subtract the mean from Jake's score:

520 - 500 = 20

Divide by the standard deviation:

20/60 = 0.33

Jake scored 0.33 standard deviation above the mean.

From the Z-table, 0.33 = 0.6293 = 62.93% of students scored below Jake.

Round to 63%

table a is wierd

step-by-step explanation:

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