The sum of three numbers is 26. the second number is twice the first and the third number is 6 more than the second. find the numbers.

ANSWER

EXPLANATION

Let the first number be

Then the second number will be

and the third number is

The sum of these numbers is 26.

This implies that;

Group similar terms;

Simplify;

Divide both sides by 5

This gives us;

The numbers are:

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3