Figure these out, and explain how! you so much!

area of circle: πr^2

area of square: l * w (or l * l)

16.

we are looking for the area of the larger circle with the area of the tiny circle in the middle.

to start we can find the area of the larger circle.

the radius is half the diameter, so r=6.

π(6^2) = 113.04

next we should find the area of the tiny circle.

8/2 = 4; r = 4

π(4^2) = 50.24

so to find the area of the shaded parts, we can subtract the area of the big circle with the tiny one.

113.04 - 50.24 = 62.8m^2

17.

now we are looking for the area of a square minus the area of the circle inside

let's find the area of the square

5.25 * 5.25 = 27.5625

next the circle,

the diameter is 5.25, so r= 2.625

π(2.625^2) = 21.6365625

finally we subtract the area of the square with that of the circle

27.5625 - 21.6365625 = 5.9259375 or

5.9in^2

18.

now we are looking for the area of a circle minus 2 tiny ones inside of it.

area of big circle:

12.5/2 = 6.25

π(6.25^2) = 122.65625

area of tiny circle:

1.5/2 = 0.75

π(0.75^2) = 1.76625

finally we do area of big circle minus 2 of the tiny circles

122.65625 - 2(1.76625) = 119.12375 or

119.1cm^2

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day

i suppose it should be (y=2x-5)

step-by-step explanation: