Which of the following is the equation of a line that passes through the points (1,6) and (2,1)
a. y=-5x+11
b. y=-5x+1
c. y=2x+1
d. y=5x-1

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (1, 6) and (x₂, y₂ ) = (2, 1)

m = = - 5, hence

y = - 5x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (1, 6), then

6 = - 5 + c ⇒ c = 6 + 5 = 11

y = - 5x + 11 → A

Step-by-step explanation:

Given :  Points (1,6) and (2,1)

To Find : Which of the following is the equation of a line that passes through the points (1,6) and (2,1) ?

Solution:

Now to find the equation of a line that passes through the points (1,6) and (2,1) we will use two point slope form

Two point slope form :

Substitute the values

So, Option A is true.

Hence The equation of a line that passes through the points (1,6) and (2,1) is

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step-by-step explanation:

answer:

a=9

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