You!

which list is in order from largest to smallest?
a.
0.6 × 10-4 , 1.1 × 10-3 , 1.1 × 10-4
b.
1.1 × 10-3 , 1.1 × 10-4 , 0.6 × 10-4
c.
1.1 × 10-3 , 0.6 × 10-4 , 1.1 × 10-4
d.
0.6 × 10-4 , 1.1 × 10-4 , 1.1 × 10-3

A= 3.6, 7.7, 6.6

B= 7.7, 6.6, 3.6

C= 7.7, 3.6, 6.6

D= 3.6, 6.6, 7.7

.•. B is the answer

*if not done by BODMAS

A= 2, 8, 7

B= 8, 7, 2

C= 8, 2, 7

D= 2, 7, 8

.•. B is the answer

*if done by BODMAS

hope it helps you mate thanks for the question and if possible please mark it as brainliest

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.

answer:

24pi or letter c