I'm having a lot of trouble with this !

kayla wants to find the distance, ab, across a creek. she starts at point b and walks along the edge of the river 62 ft and marks point c. then she walks 93 ft further and marks point d. she turns 90° and walks until her final location and marks point e. point e, point a, and point c are collinear.

(a) can kayla conclude that ∆abc and ∆edc are similar? why or why not?

(b) suppose (de) ̅=125 ft. calculate the distance of (ab) ̅ to the nearest tenth of a foot. show your work. don’t forget to label your answer.

a ∆ABC and ∆EDC are similar

b. AB = 83.3 ft

Step-by-step explanation:

a.  We need to determine if  ∆ABC and ∆EDC are similar.

We know B = D = 90

We know C = C because they are vertical angles and vertical angles are equal

Therefore A = E because they are triangles, and if 2 angles in a triangle are equal the third angles must be equal.

∆ABC and ∆EDC are similar

b.  We know that because they are similar triangles

AB      BC

=

ED        DC

Substituting in

AB       62

=

125        93

Using cross products

93 AB = 62*125

93 AB = 7750

Divide by 93

AB = 7750/93

AB = 83.3333333333(repeating)

Rounding to the nearest tenth ft

AB = 83.3 ft

d≈7.07in

step-by-step explanation: