Mathematics, 30.01.2020 14:05 makayladurham19

Given: lm ∥ kn, kl ∥ nm

lp = h1 = 5, mq = h2 = 6

perimeter of klmn = 42

find: area of klmn

Given: lm ∥ kn, kl ∥ nmlp = h1 = 5, mq = h2 = 6 perimeter of klmn =

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Given: lm ∥ kn, kl ∥ nm

lp = h1 = 5, mq = h2 = 6

perimeter of klmn = 42