The coordinates of pqr are p(1, 1), q(2, 2), and r(3, 1). if pqr is rotated 90° about the origin, what are the vertices of p'q'r'?

(-1, 1), (-2, 2), and (-1, 3)

Step-by-step explanation:

The formula for rotation of a point (x,y) by an angle θ about the origin is  

x' = xcosθ  -  ysinθ

y' = ycosθ + xsinθ

If θ = 90°, sinθ = 1 and cosθ = 0, and the formula becomes

x' = -y

y' =  x

P: (1, 1)   ⟶ (-1,  1)

Q:(2, 2) ⟶ (-2, 2)

R: (3, 1) ⟶  (-1,  3)  

The vertices of P'Q'R' are (-1, 1), (-2, 2), and (-1, 3).

The Figure below shows the triangle before and after the rotation.

what is the question here

step-by-step explanation:

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00