Which comparison is correct for the values of f(x) and g(x) when x=−2 ? function a: f(x)=3−x2 function b: x g(x) −2 −1 −1 0 0 2 1 −3 f(−2)=g(−2) f(−2)> g(−2) f(−2)

f(-2) = g(-2)

Explanation:

1- Consider the function f(x):

We are given that:

f(x) = 3 - x²

To get f(-2), we will substitute with x = 2 in the given function

This is done as follows:

f(-2) = 3 - (-2)²

f(-2) = 3 - 4

f (-2) = -1

2- Consider the function g(x):

We are given the table of g(x) as follows:

x > y

-2 > -1

-1 > 0

0 > 2

1 > -3

Therefore, we can directly conclude that:

g(-2) = -1

3- Comparing the values:

From the above, we can note that f(-2) = -1 and g(-2) = -1

Therefore the two values are equal

Hope this helps :)

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

50-60=10

step-by-step explanation: