You want to fence in a row bed that is adjacent to a deck. the length of your deck is 14ft. you have at most 44 ft of fence. what are the possible widths of the rose bed?

he first step in a problem like this (after sketching the problem out for yourself, which very often helps) is to assign variables.  Let's call the length x, and the width y.

There are two sections that are y long, and one that's x long.  Adding up the total length of the fence, then, gives us x + y + y, or x + 2y, which should be equal to 44, since that's how much fence we have.  Our first equation is thus

x + 2y = 44

Our second equation, since the length is supposed to be twice the width, is x = 2y.

This is enough to solve.  We can substitute this equation for x into the first equation to get

2y + 2y = 44

4y = 44

y = 11

And then x = 2(11) = 22

So the length of the fence is 22, and the width (though they don't actually ask for it) is 11.

Check the  22 + 11 + 11 is 44, as we want, and 22 is twice as great as 11, as we want.  So the answer is valid.

Step-by-step explanation:

Okay so one way you can do this is in a rectangle yard that is 14 by 8 the rose bed can be any where less than 8 ft and still be adjacent to the deck. hope this helps!   :)

is only a line? i think so

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: