Raul bought a soft drink and a sandwich for $9.90. what is the price of each if the sandwich cost 3.5 times as much as the soft drink?
a) sandwich costs $5.94 and the soda costs $3.96
b) sandwich costs $7.70 and the soda costs $2.20
c) sandwich costs $5.40 and the soda costs $4.50
d) sandwich costs $2.83 and the soda costs $9.90

First create a ratio:

The sandwich cost 3.5 more than the drink therefore the ratio is 3.5:1

Then add the two sides of the ratio together to get the total parts of the ratio
3.5+1 = 4.5

Now that we know the total parts of the ratio we can solve for one part by dividing the total cost $9.90 by the total parts of the ratio 4.5+

$9.90/4.5 = 2.20

Since we know that each part of the ratio is 2.20 we multiply both sides of the ratio by 2.20

3.5 *2.20 = 7.70
1 * 2.20 = 2.20

Therefore the answer is B

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)

Anyone can me with these answers