What is: x (80 - 75 x) - [500 + 2 (80 - 0.75 x)]- 250 - 3 (80 - .75x)

=−75x2+81.5x−1147.75

Step-by-step explanation:

simplify step-by-step.

x(80−75x)−(500+2(80−0.75x))−250−3(80−0.75)

Distribute:

=(x)(80)+(x)(−75x)+−500+(−2)(80)+(−2)(−0.75x)+−250+−3(80−0.75)

=80x+−75x2+−500+−160+1.5x+−250+−237.75

Combine Like Terms:

=80x+−75x2+−500+−160+1.5x+−250+−237.75

=(−75x2)+(80x+1.5x)+(−500+−160+−250+−237.75)

=−75x2+81.5x+−1147.75

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

sadsdda

step-by-step explanation: