Hurry will mark brainiest this is an easy question

find the probability that a roll of two dice will produce a sum of either 7 or 11

how many times would you expect this to occur in 50 trials?

first qn

4/36=1/9

total no. of ways to roll a dice=36

no. of ways to produce 7=3

(1+6=7, 2+5=7, 3+4=7)

no. of ways to produce 11=1

(5+6=11)

there are 4 ways in total. 4/36 simplify it to be 1/9

second qn im not sure but i think its

1/9 x 50 = 50/9 = 5 x (5/9)

round it off to the smaller whole no. which is 5 so i think its 5 times in 50 trials

goog may have it for you

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length