Amuseum requires a minimum number of chaperones proportional to the number of students on a field trip. the museum requires a minimum of 3 chaperones for a field trip with 24 students. which of the following could be combinations of values for the students and the minimum number of chaperones the museum requires? choose 2 answers:

a. students: 72
minimum of chaperones: 9

b. students: 16
minimum of chaperones: 2

c. students: 60
minimum of chaperones: 6

d. students: 45
minimum of chaperones: 5

e. students: 40
minimum of chaperones: 8

The combination of values for the students and at least no of chaperones the museum needed is option A and option B.

Given that

There is a minimum no of chaperones required i.e. 3.

And, there are 24 students.

So,  if we divided the 24 by 3 so we can get the 8 students for one chaperone.

Now as per the given options:

A.

= 8 students per chaperone.

B.

=  8 students per chaperone.

C.

= 10 students per chaperone.

D.

= 9 students per chaperone.

E.

= 5  students per chaperone.

Therefore we can conclude that the combination of values for the students and at least no of chaperones the museum needed is option A and option B.

Learn more about the proportions here: link

24 students divided by 3 chaperones equals 1 chaperone for every 8 students.

A. 72 / 9 = 8 students per chaperone.  This is correct.

B. 16 / 2 = 8 students per chaperone. This is correct.

C. 60 / 6 = 10 students per chaperone. This is not correct.

D. 45 / 5 = 9 students per chaperone. This is not correct.

E. 40 / 8 = 5 students per chaperone. This is not correct.

The 2 correct answers are A and B.

b.an increase in a causes b to decrease

answer: okw

step-by-step explanation: