Let f(x)=x^2+10x+29 .

what is the minimum value of the function?

enter your answer in the box.

4

Step-by-step explanation:

given

f(x) = x² + 10x + 29

Since the coefficient of the x² term > 0, f(x) will have a minimum value

Use the method of completing the square

add/ subtract ( half the coefficient of the x- term )² to x² + 10x

f(x) = x² + 2(+ 5)x + (5)² - (5)² + 29

    = (x + 5)² - 25 + 29

   = (x + 5)² + 4

When x = - 5 , f(x) has a minimum value at + 4

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

the first one

step-by-step explanation:

just id the test.