Determine the quotient q(x) and remainder r(x) when f(x)=18x^4+27x^3+39x^2+22x+11
is divided by g(x)=3x^2+3x+4

, and

Subtracting this from gives a remainder of

, and

Subtracting this from the previous remainder gives a new remainder of

, and

Subtracting this from the previous remainder gives a new remainder of

is not divisible by , so we're done. We ended up with

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine