The area of a trapezoid with height z is 20 sq .cm. the length s of the parallel sides are (2z+3) and (6z-1) cm. find the height of the trapezoid. in your final answer, include all of the formulas and calculations necessary to solve for the height.

Area of a trapezoid = ½(a + b)h, where a and b are the lengths of the parallel sides and h is its height. 

From your information 20 = ½(2z + 3 + 6z – 1)z = ½(8z + 2)z = z(4z + 1) 

Solve 20 = 4z² + z which is 0 = 4z² + z – 20 using the quadratic formula 

Step-by-step explanation:

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: