Rosetta wants to write equations in the form y=mx+b for the lines passing through point p that are parallel and perpendicular to line g. first she finds the slopes of these two lines. what could she do next to find the y-intercepts?

a. substitute the slope and the coordinates of point p in y=mx+b and then solve for b for each equation.
b. multiply the slope by the x-coordinate and add the y-coordinate to the product.
c. multiply the slope by the y-coordinate and subtract the result from the x-coordinate.
d. solve the proportion m/b=y/x for b.

A. Substitute the slope and the coordinates of point P in y=mx+b and then solve for b for each equation.

Step-by-step explanation:

We know the equation for a line passing through a point P(x,y) is given as:

y = mx + b

where

m is the slope of the line.

x, y are the co-ordinates of point P.

b is the y-intercept of line on point P(x,y).

If g is the line. we find its slop m. Let's the slope 'm' is given as m = b/a

The slope of lines parallel to line g is b/a.

The slope of lines perpendicular to line g is -a/b.

Substituting the slope and and coordinates of point P and then solving for b will give us the y-intercept.

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic