Aball is thrown vertically upward. after t seconds, its height h (in feet) is given by the function h(t)=92t-16t^2. what is the maximum height that the ball will reach? do not round your answer

The maximum height that the ball will reach : 132.25 ft

Quadratic function is a function that has the term x²

The quadratic function forms a parabolic curve

The general formula is

f (x) = ax² + bx + c

where a, b, and c are real numbers and a ≠ 0.

The parabolic curve can be opened up or down determined from the value of a. If a is positive, the parabolic curve opens up and has a minimum value.   If a is negative, the parabolic curve opens down and has a maximum value

So the maximum is if a <0 and the minimum if a> 0.

The formula for finding the coordinates of the maximum and minimum points of the quadratic function is the same.

The maximum / minimum point of the quadratic function is

Where

h height of the ball is given by the function h (t) = 92t-16t².

so the value of a <0, then it has a maximum value

Because we are looking for maximum height, then we find the value of the y coordinate, with the formula

h (t) = 92t-16t²

a = -16 b = 92 c = 0

D = b²-4ac

D = 92²-4.-16.0

D = 8464

Value of y = maximum height (h):

domain of the function

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the inverse of the ƒunction

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F (x) = x2 + 1 g (x) = 5 - x

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step-by-step explanation:

|ab| = 1.4 = 4

h = 1.4 = 4

a(abc) area = 4.4 = 16/2 = 8

area of abc = 8 cm^2

good luck ! ; )

left 3, up 4

step-by-step explanation:

just count the values of x & y of the vertex of the graph and see how many units in the x and y direction will get you from the f(x) graph to the f(x) graph