Arectangle has a perimeter of 20 inches and an area of 24 square inches. what are the length and width of the rectangle?

Length = 6in

Width = 4in

Step-by-step explanation:

The formula for solving the perimeter of a rectangle is:

P = 2(L+W)

The formula for finding the area of a rectangle is:

A = L x W

If we substitute our values, we will get:

P = 2(6 + 4)

P = 2(10)

P = 20in

A = 6 x 4

A = 24in²

When l = 6 ⇒ w = 4

when l = 4 ⇒w = 6

Step-by-step explanation:

We have given perimeter and area of rectangle.

Perimeter  = P = 20 inches and Area  = A  = 24 square inches

We have to find the length and width of the rectangle.

Let l is length and w is width of rectangle.

The formula  of Perimeter is :

P = 2(l+w)

The formula of area is :

A  = l × w

Given values :

P  = 2(l+w)  = 20

l+w  = 10

w  = 10-l                                      eq(1)

A  = l × w  = 24                           eq(2)

Putting eq(1) in eq(2), we have

A  = l × (10-l)  = 24

10l-l² = 24

l²-10l +24= 0

Applying factorization to above equation, we have

(l-6)(l-4) = 0

Applying Zero-Product rule , we have

l-6 = 0 or l-4 = 0

l = 6 or l = 4

Putting above values in eq(1) , we have

When l = 6 ⇒ w = 10-6

w = 4

when l = 4 ⇒w = 10-4

w = 6

Answer is :

When l = 6 ⇒ w = 4

when l = 4 ⇒w = 6

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

y -5 = (-1/4)(x + 8)

step-by-step explanation: