P=-5x^2+1000x+5000 how many computers must be sold to obtain a profit of $55,000.00?

14 computers

Step-by-step explanation:

Set the profit, p, equal to $55,000.00 and then solve for x:

-5x^2 + 1000x + 5000 = 55000

Dividing both sides by -5 results in:

x^2 - 200x - 1000 = +11000.

Combining the constant terms results in:

x^2 - 200x - 11000 = 0

Solve this by completing the square:

x^2 - 200x + 10000 - 10000 - 11000 = 0, or

  (x - 100)^2              - 21000 = 0, or

  (x - 100)^2 = 21000

Taking the square root of both sides, we get

  x - 100 =  ±10√210, or

  x = 100 ± 10√210, or approx. x = 100 + 14.5, or approx 114.5

Sellilng between 114 and 115 computers would result in a profit of $55,000.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

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step-by-step explanation: