Kathleen had a bag of candy-coated chocolates. of the 55 candies in the bag, 20% were red, 30% were orange, 30% were green, and 20% were blue. of the blue ones, 20% had a damaged candy coating. approximately how many of the blue ones had a damaged candy coating?
a.
2
b.
11
c.
22
d.
6

For this case, we find the amount of each colored candy in the bag, having a total of 55.

55 -------------> 100%

R ---------------> 20%

Where "R" represents the amount of red candies.

O = 16.5, approximately 16 orange candies.

G = 16.5, approximately 16 green candies.

Now, having a total of 11 blue candies, we must find 20% to know how many have the damaged candy coating.

11 ---------------> 100%

x -----------------> 20%

Where "x" represents the quantity of blue candies with the damaged candy coating

So, of 2 blue candies have the damaged candy coating

two

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.