Ineed with this !

f(x) = (3x^2 - 4x + 2)
g(x) = (2x^3 - 2)
find f(g(x)) and f(g(3))
show all work!

f(x)=3x+2,g(x)=2x^(2)-1

Step-by-step explanation:

First set up the composite result :

f (g (x))

Evaluate f (g (x))

3( 2x sqaured -1 ) + 2

Simplify:

f ( 2X SQUARED -1 ) 6 x squared -3 + 2

Add 2 and -3

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?