Acircular waterfall is surrounded by a brick wall. the radius of the inner wall is 35 inches. if the bricks are 5 inches wide, what scale factor was used to determine the radius of outer wall?

8:7

Step-by-step explanation:

A scale factor (SF) is the ratio of two corresponding side lengths in similar figures.

The two circles are the similar figures, and the SF is the ratio of their corresponding radii.

SF = outer radius/inner radius

    = (35 + 5)/35

    = 40/35

    = 8/7

The scale factor is 8:7.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

step-by-step explanation: