What are the intercepts of the line y=x-8

Step-by-step explanation:

You can read the graph or you can solve it. Reading the graph gives

y intercept

(0,-8)

x intercept

(8,0)

Or you can solve it by algebra

y = x - 8

The y intercept occurs when x = 0

y = 0 - 8

y = - 8

The point is (0,-8)

The x intercept occurs when y = 0

0 = x - 8                  

Add 8 on both sides

8 = x - 8 + 8

x = 8

The point is (8,0)

y=mx+b is the final answer!   : )

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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