Find the perimeter of a rectangle with length measuring 14 and width measuring 3.

34

Step-by-step explanation:

If you were to draw this rectangle, you can see that it has 2 sides measuring 14 and 2 sides measuring 3.

To solve for the perimeter, you add up all of the sides.

14 + 3 + 14 + 3 = 34

Therefore, the perimeter of a 14x3 rectangle is 34.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !