What are the zeros of the quadratic function? f(x)=2x^2+x−3

x = 1  and x = - 3/2

Step-by-step explanation:

the zeros of the quadratic function when f(x) = 0

So

2x^2+x−3 = 0

Factor:

2x^2+x−3 = 0

(2x + 3)(x - 1) = 0

2x + 3 = 0;x = - 3/2

x - 1 = 0; x = 1

x = 1  and x = - 3/2

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation: