Which is the solution set to the given inequality |x+3|< 12? x infinity(-15,9), x infinity {-15,9], x infinity (00,-15)u(9,00), x infinity (-00,-15)n(9,00)

which ordered pair is a solution to the system?
{y> -2
{x + y less than or equal to 4

(1,5)
(0,5)
(-2,-3)
(1,3)

i really need i am failing algebra ii and just can't seem to understand it or graphing

Part 1) The solution set is (-15,∞) ∩ (-∞,9)=(-15,9)

Part 2) The ordered pair (1,3) is a solution of the system

Step-by-step explanation:

Part 1) we have

First solution case Positive

The solution first case is the interval -------> (-∞,9)

Second solution case Negative

------> Multiply by -1 both sides

The solution second case is the interval -------> (-15,∞)

The solution set is equal to

(-15,∞) ∩ (-∞,9)=(-15,9)  

Part 2) we have

-------> inequality A

-----> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

Verify each case

case a) (1,5)

Substitute the value of x and the value of y in the inequality and then compare

Inequality A

------> is true

Inequality B

-----> is not true

therefore

the ordered pair is not a solution

case b) (0,5)

Substitute the value of x and the value of y in the inequality and then compare

Inequality A

------> is true

Inequality B

-----> is not true

therefore

the ordered pair is not a solution

case c) (-2,-3)

Substitute the value of x and the value of y in the inequality and then compare

Inequality A

------> is not true

therefore

the ordered pair is not a solution

case d) (1,3)

Substitute the value of x and the value of y in the inequality and then compare

Inequality A

------> is true

Inequality B

-----> is true

therefore

the ordered pair is  a solution

step-by-step explanation: