Which quadratic function opens down and has a vertex with a negative y value?
a. f(x)= 5x^2-18
b. g(x)= -4x^2+7x+20
c. h(x)= -1/2(x-9)^2+1
d. j(x)= -10(x+6)^2 -3

It's D.

Step-by-step explanation:

The function with a negative coefficient of x^2 will open downwards so its either B, C or D. The y value of the vertex is the last constant.

So the answer is D  with negative y value -3.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation: