Solve the compound inequality 8x > –32 or 6x ≤ –48.
–4 > x ≥ –8
x > –4 or x ≤ –8
–4 < x ≥ –8
x < –4 or x ≤ –8

The second alternative is the correct answer

Step-by-step explanation:

We are given the inequality;

8x > -32

To solve for x we simply divide both sides by 8 and this will yield;

x > -4

For the second inequality;

6x ≤ -48

we divide both sides by 6 and solve for x;

x ≤ -8

Therefore the solution to the compound inequality is thus;

x > –4 or x ≤ –8

nothjing

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.